Optimal. Leaf size=200 \[ -\frac{b^3 \sqrt{a^2+2 a b x+b^2 x^2}}{5 e^4 (a+b x) (d+e x)^5}+\frac{b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}{2 e^4 (a+b x) (d+e x)^6}-\frac{3 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{7 e^4 (a+b x) (d+e x)^7}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{8 e^4 (a+b x) (d+e x)^8} \]
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Rubi [A] time = 0.0868989, antiderivative size = 200, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {646, 43} \[ -\frac{b^3 \sqrt{a^2+2 a b x+b^2 x^2}}{5 e^4 (a+b x) (d+e x)^5}+\frac{b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}{2 e^4 (a+b x) (d+e x)^6}-\frac{3 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{7 e^4 (a+b x) (d+e x)^7}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{8 e^4 (a+b x) (d+e x)^8} \]
Antiderivative was successfully verified.
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Rule 646
Rule 43
Rubi steps
\begin{align*} \int \frac{\left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^9} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \frac{\left (a b+b^2 x\right )^3}{(d+e x)^9} \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \left (-\frac{b^3 (b d-a e)^3}{e^3 (d+e x)^9}+\frac{3 b^4 (b d-a e)^2}{e^3 (d+e x)^8}-\frac{3 b^5 (b d-a e)}{e^3 (d+e x)^7}+\frac{b^6}{e^3 (d+e x)^6}\right ) \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=\frac{(b d-a e)^3 \sqrt{a^2+2 a b x+b^2 x^2}}{8 e^4 (a+b x) (d+e x)^8}-\frac{3 b (b d-a e)^2 \sqrt{a^2+2 a b x+b^2 x^2}}{7 e^4 (a+b x) (d+e x)^7}+\frac{b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}{2 e^4 (a+b x) (d+e x)^6}-\frac{b^3 \sqrt{a^2+2 a b x+b^2 x^2}}{5 e^4 (a+b x) (d+e x)^5}\\ \end{align*}
Mathematica [A] time = 0.046937, size = 112, normalized size = 0.56 \[ -\frac{\sqrt{(a+b x)^2} \left (15 a^2 b e^2 (d+8 e x)+35 a^3 e^3+5 a b^2 e \left (d^2+8 d e x+28 e^2 x^2\right )+b^3 \left (8 d^2 e x+d^3+28 d e^2 x^2+56 e^3 x^3\right )\right )}{280 e^4 (a+b x) (d+e x)^8} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.155, size = 131, normalized size = 0.7 \begin{align*} -{\frac{56\,{x}^{3}{b}^{3}{e}^{3}+140\,{x}^{2}a{b}^{2}{e}^{3}+28\,{x}^{2}{b}^{3}d{e}^{2}+120\,x{a}^{2}b{e}^{3}+40\,xa{b}^{2}d{e}^{2}+8\,x{b}^{3}{d}^{2}e+35\,{a}^{3}{e}^{3}+15\,d{e}^{2}{a}^{2}b+5\,a{b}^{2}{d}^{2}e+{b}^{3}{d}^{3}}{280\,{e}^{4} \left ( ex+d \right ) ^{8} \left ( bx+a \right ) ^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.84164, size = 406, normalized size = 2.03 \begin{align*} -\frac{56 \, b^{3} e^{3} x^{3} + b^{3} d^{3} + 5 \, a b^{2} d^{2} e + 15 \, a^{2} b d e^{2} + 35 \, a^{3} e^{3} + 28 \,{\left (b^{3} d e^{2} + 5 \, a b^{2} e^{3}\right )} x^{2} + 8 \,{\left (b^{3} d^{2} e + 5 \, a b^{2} d e^{2} + 15 \, a^{2} b e^{3}\right )} x}{280 \,{\left (e^{12} x^{8} + 8 \, d e^{11} x^{7} + 28 \, d^{2} e^{10} x^{6} + 56 \, d^{3} e^{9} x^{5} + 70 \, d^{4} e^{8} x^{4} + 56 \, d^{5} e^{7} x^{3} + 28 \, d^{6} e^{6} x^{2} + 8 \, d^{7} e^{5} x + d^{8} e^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17929, size = 228, normalized size = 1.14 \begin{align*} -\frac{{\left (56 \, b^{3} x^{3} e^{3} \mathrm{sgn}\left (b x + a\right ) + 28 \, b^{3} d x^{2} e^{2} \mathrm{sgn}\left (b x + a\right ) + 8 \, b^{3} d^{2} x e \mathrm{sgn}\left (b x + a\right ) + b^{3} d^{3} \mathrm{sgn}\left (b x + a\right ) + 140 \, a b^{2} x^{2} e^{3} \mathrm{sgn}\left (b x + a\right ) + 40 \, a b^{2} d x e^{2} \mathrm{sgn}\left (b x + a\right ) + 5 \, a b^{2} d^{2} e \mathrm{sgn}\left (b x + a\right ) + 120 \, a^{2} b x e^{3} \mathrm{sgn}\left (b x + a\right ) + 15 \, a^{2} b d e^{2} \mathrm{sgn}\left (b x + a\right ) + 35 \, a^{3} e^{3} \mathrm{sgn}\left (b x + a\right )\right )} e^{\left (-4\right )}}{280 \,{\left (x e + d\right )}^{8}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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